0.3t^2-27t+303.75=0

Solution for 0.3t^2-27t+303.75=0 equation:

0.3t^2-27t+303.75=0

a = 0.3; b = -27; c = +303.75;
Δ = b2-4ac
Δ = -272-4·0.3·303.75
Δ = 364.5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{364.5}}{2*0.3}=\frac{27-\sqrt{364.5}}{0.6}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{364.5}}{2*0.3}=\frac{27+\sqrt{364.5}}{0.6}
$